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GATE BT-2017 Answer Key | Solutions Discussion
Guys...how many questions r going to be challenged?
And who is challenging what?
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(03-01-2017, 11:40 PM)sadaf188 Wrote: Sunil sir....the solution I have figured out of ques 16 is y=x^3....nd it satisfies all d conditions.
Nd if y is constant i.e., y=1, then there is no point of giving y=f(x)
This is wat I thought.

hi,
Are u planning to challenge this question? Even i approached this question in this same method.
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No....I m not challenging this one....becoz my teacher told me...how d answer is one.
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Did anyone started challenging, if yes than post the question which is challenged , so others cannot challenge on the same question.
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(03-03-2017, 06:13 PM)kashyap.aluru Wrote: Did anyone started challenging, if yes than post the question which is challenged , so others cannot challenge on the same question.
Not yet started but I will challenge ques 49
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has anyone challenged pedigree, question
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(03-03-2017, 11:40 PM)ajanthpraveen Wrote: has anyone challenged pedigree, question
Not me
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(03-02-2017, 05:15 PM)masthanbasha Wrote:
(03-02-2017, 02:49 PM)RahulK Wrote: For the Pedigree question: 

I found the below images from book :

Genetics : A conceptual Approach by Benjamin A Pierce

Image 1: Shows the standard symbols used in pedigree chart

Image 2: Shows a pedigree chart which is somewhat similar to the gate question pedigree chart

Besides that 

I went through a video on NPTEL course "Human Molecular Genetics" which is on pedigree analysis at this link :


http://nptel.ac.in/courses/102104052/5

Between minute 32 and 33 of the video professor says that the carriers in "x linked recessive condition" are denoted by a "dot within the circle". 
We can challenge the question giving the reason that no clear indication is given if any of the females in the given pedigree are carriers thus X linked recessive condition was not indicative from the given pedigree. 

I think these should make a strong case for review of Pedigree question and hold in favour of us because it is in the NPTEL cource lecture as well as a standard book.



Smile Smile

the google image of y linked inheritence as same as given question and u r explanation also perfect and the three questions are very meanful for challenge

The given pedigree analysis can’t be x linked recessive due to following reasons-
  1. X linked recessive is passed from mother to son and never from father to son. (1)
  2. For the  given pedigree to be x linked recessive the mother in first progeny has to be carrier but in that case  they should have 1 carrier daughter, 1 healthy son, 1 affected daughter, and 1 affected son which is not the case.(2)
  3. For all the affected males the disease is being passed on to the son  and for that to happen all the females , even ones who married the affected sons (marked as 6 and 9 in the attached file) have to be carrier. Chances for that are very low.
  4. The given pedigree is a classic case of Y linked inheritance for the disease Hairy ears and Retinitis pigmentosa(3)


References
  1. (Figure 4-24), https://www.ncbi.nlm.nih.gov/books/NBK21257/
  2. https://www.ncbi.nlm.nih.gov/books/NBK21257/
  3. https://migrc.org/Library/Ylinked.html
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(03-04-2017, 04:22 AM)rizviaijaz08 Wrote:
(03-02-2017, 05:15 PM)masthanbasha Wrote: the google image of y linked inheritence as same as given question and u r explanation also perfect and the three questions are very meanful for challenge

The given pedigree analysis can’t be x linked recessive due to following reasons-
  1. X linked recessive is passed from mother to son and never from father to son. (1)
  2. For the  given pedigree to be x linked recessive the mother in first progeny has to be carrier but in that case  they should have 1 carrier daughter, 1 healthy son, 1 affected daughter, and 1 affected son which is not the case.(2)
  3. For all the affected males the disease is being passed on to the son  and for that to happen all the females , even ones who married the affected sons (marked as 6 and 9 in the attached file) have to be carrier. Chances for that are very low.
  4. The given pedigree is a classic case of Y linked inheritance for the disease Hairy ears and Retinitis pigmentosa(3)


References
  1. (Figure 4-24), https://www.ncbi.nlm.nih.gov/books/NBK21257/
  2. https://www.ncbi.nlm.nih.gov/books/NBK21257/
  3. https://migrc.org/Library/Ylinked.html

aijaz n rahul u guys are challenging the pedigree question
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(03-04-2017, 04:22 AM)rizviaijaz08 Wrote:
(03-02-2017, 05:15 PM)masthanbasha Wrote: the google image of y linked inheritence as same as given question and u r explanation also perfect and the three questions are very meanful for challenge

The given pedigree analysis can’t be x linked recessive due to following reasons-
  1. X linked recessive is passed from mother to son and never from father to son. (1)
  2. For the  given pedigree to be x linked recessive the mother in first progeny has to be carrier but in that case  they should have 1 carrier daughter, 1 healthy son, 1 affected daughter, and 1 affected son which is not the case.(2)
  3. For all the affected males the disease is being passed on to the son  and for that to happen all the females , even ones who married the affected sons (marked as 6 and 9 in the attached file) have to be carrier. Chances for that are very low.
  4. The given pedigree is a classic case of Y linked inheritance for the disease Hairy ears and Retinitis pigmentosa(3)


References
  1. (Figure 4-24), https://www.ncbi.nlm.nih.gov/books/NBK21257/
  2. https://www.ncbi.nlm.nih.gov/books/NBK21257/
  3. https://migrc.org/Library/Ylinked.html

and the cytokinesis inhibition one was the cplchicine correct answer for it
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