Contact:
sales@biotechnologyforums.com to feature here

Thread Rating:
  • 2 Vote(s) - 3 Average
  • 1
  • 2
  • 3
  • 4
  • 5
GATE BT-2017 Answer Key | Solutions Discussion
#72
(02-14-2017, 09:45 PM)CHANDA7 Wrote: Can anyone answer this question?

At the transcription start site of a gene, any of the four nucleotides can occur with equal probability p. 
The Shannon Entropy S for this site would be? (Details in the image)
Given the fact that there is equal Probability for all 4 nucleotides, so p=0.25 or 1/4.

Now, all we have to do is fill the same into the given equation:

S= -[0.25*ln(0.25) + 0.25*ln(0.25) + 0.25*ln(0.25) + 0.25*ln (0.25)]

= -0.25[4ln(0.25)]
=-1*ln(0.25)
=-ln(0.25)
=-ln(1/4)
=-[ln(1) - ln(4)]
= -[0 - ln (2*2)]
= ln(2) +ln (2)
=0.69 + 0.69
= 1.38

I hope this is the way to go about it...
Sunil Nagpal
MS(Research) Scholar, IIT Delhi (Alumnus)
Advisor for the Biotech Students portal (BiotechStudents.com)
Computational Researcher in BioSciences at a leading MNC


Suggested Reads:
Top Biotech Companies | Top places to work
Indian Biotech Companies and Job Openings
Aiming a PhD in Top Grad School? | These are the Important Points to Consider
Careers in Biotechnology | A list of various Options
Biotechnology Competitive Exams in India
Like Post Reply
  


Messages In This Thread
RE: GATE BT-2017 Answer Key | Solutions Discussion - by SunilNagpal - 02-15-2017, 01:56 AM
A GATE BT Marks Survey Page - by reviewer21 - 02-28-2017, 05:31 AM
RE: A GATE BT Marks Survey Page - by SunilNagpal - 03-01-2017, 02:09 AM
RE: A GATE BT Marks Survey Page - by CHANDA7 - 02-28-2017, 04:37 PM
Possibly Related Threads…
Thread
Author
  /  
Last Post
Replies: 0
Views: 6,828
06-26-2018, 05:23 PM
Last PostSudhira
Replies: 0
Views: 7,903
05-31-2018, 03:34 PM
Last Postyamuna
Replies: 0
Views: 6,960
11-29-2017, 02:54 AM
Last PostPriyanka .P
Replies: 2
Views: 14,555
11-17-2017, 11:23 PM
Last Postdeeba



Users browsing this thread:
9 Guest(s)

GATE BT-2017 Answer Key | Solutions Discussion32