03-03-2017, 03:26 AM
Guys...how many questions r going to be challenged?
And who is challenging what?
And who is challenging what?
(03-01-2017, 11:40 PM)sadaf188 Wrote: Sunil sir....the solution I have figured out of ques 16 is y=x^3....nd it satisfies all d conditions.
Nd if y is constant i.e., y=1, then there is no point of giving y=f(x)
This is wat I thought.
(03-02-2017, 05:15 PM)masthanbasha Wrote:(03-02-2017, 02:49 PM)RahulK Wrote: For the Pedigree question:
I found the below images from book :
Genetics : A conceptual Approach by Benjamin A Pierce
Image 1: Shows the standard symbols used in pedigree chart
Image 2: Shows a pedigree chart which is somewhat similar to the gate question pedigree chart
Besides that
I went through a video on NPTEL course "Human Molecular Genetics" which is on pedigree analysis at this link :
http://nptel.ac.in/courses/102104052/5
Between minute 32 and 33 of the video professor says that the carriers in "x linked recessive condition" are denoted by a "dot within the circle".
We can challenge the question giving the reason that no clear indication is given if any of the females in the given pedigree are carriers thus X linked recessive condition was not indicative from the given pedigree.
I think these should make a strong case for review of Pedigree question and hold in favour of us because it is in the NPTEL cource lecture as well as a standard book.
the google image of y linked inheritence as same as given question and u r explanation also perfect and the three questions are very meanful for challenge
(03-04-2017, 04:22 AM)rizviaijaz08 Wrote:(03-02-2017, 05:15 PM)masthanbasha Wrote: the google image of y linked inheritence as same as given question and u r explanation also perfect and the three questions are very meanful for challenge
The given pedigree analysis can’t be x linked recessive due to following reasons-
- X linked recessive is passed from mother to son and never from father to son. (1)
- For the given pedigree to be x linked recessive the mother in first progeny has to be carrier but in that case they should have 1 carrier daughter, 1 healthy son, 1 affected daughter, and 1 affected son which is not the case.(2)
- For all the affected males the disease is being passed on to the son and for that to happen all the females , even ones who married the affected sons (marked as 6 and 9 in the attached file) have to be carrier. Chances for that are very low.
- The given pedigree is a classic case of Y linked inheritance for the disease Hairy ears and Retinitis pigmentosa(3)
References
(03-04-2017, 04:22 AM)rizviaijaz08 Wrote:(03-02-2017, 05:15 PM)masthanbasha Wrote: the google image of y linked inheritence as same as given question and u r explanation also perfect and the three questions are very meanful for challenge
The given pedigree analysis can’t be x linked recessive due to following reasons-
- X linked recessive is passed from mother to son and never from father to son. (1)
- For the given pedigree to be x linked recessive the mother in first progeny has to be carrier but in that case they should have 1 carrier daughter, 1 healthy son, 1 affected daughter, and 1 affected son which is not the case.(2)
- For all the affected males the disease is being passed on to the son and for that to happen all the females , even ones who married the affected sons (marked as 6 and 9 in the attached file) have to be carrier. Chances for that are very low.
- The given pedigree is a classic case of Y linked inheritance for the disease Hairy ears and Retinitis pigmentosa(3)
References
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