(02-15-2017, 04:23 AM)Akshay shinde Wrote: One hundred E coli cells are infected by a single lambda phage particle. the ratio of the number of phage particles committing to lysogeny to those committing to lysis is 4:1. Assuming that the average burst size is 80 , the number of free phage particles released after on round of infection is?
What must Ben the solution for this numerical ? Kindly answer..
(02-15-2017, 04:23 AM)Akshay shinde Wrote: One hundred E coli cells are infected by a single lambda phage particle. the ratio of the number of phage particles committing to lysogeny to those committing to lysis is 4:1. Assuming that the average burst size is 80 , the number of free phage particles released after on round of infection is?
I am sorry if I'm missing some crucial information regarding lytic and lysogenic cycles (which should have been used for approaching this question), I am rather assuming it as a simplistic question....
Given the 4:1 for lysogenic : lytic phages, it is clear than 20 would be lytic phages.
Now each E.coli will burst once 80 particles have been accumulated.
(02-15-2017, 04:23 AM)Akshay shinde Wrote: One hundred E coli cells are infected by a single lambda phage particle. the ratio of the number of phage particles committing to lysogeny to those committing to lysis is 4:1. Assuming that the average burst size is 80 , the number of free phage particles released after on round of infection is?
I am sorry if I'm missing some crucial information regarding lytic and lysogenic cycles (which should have been used for approaching this question), I am rather assuming it as a simplistic question....
Given the 4:1 for lysogenic : lytic phages, it is clear than 20 would be lytic phages.
Now each E.coli will burst once 80 particles have been accumulated.
So total free particles should be 20x80 = 1600
Thank you sir for the solution . I believe it is a simple numerical as I guess there is no other possible approach for this numerical .
Q: Transcription factor X binds a 10bp DNA. X was found to bind at 20 distinct sites, distribution is as following. What is the Consensus sequence pattern.
02-15-2017, 07:34 PM (This post was last modified: 02-15-2017, 07:35 PM by SunilNagpal.)
(02-15-2017, 07:00 PM)Manoj_Shastry Wrote: Q: Transcription factor X binds a 10bp DNA. X was found to bind at 20 distinct sites, distribution is as following. What is the Consensus sequence pattern.
Option (A) NGTCNNNTNN seems most acceptable consensus (assuming a >=95% confidence).
Q: A bacteria has genome of size 6 million bp. If DNA synthesis rate is 1000 bp/ second. How long does it take (in minutes) for replication of genome?
Q: A proto-oncogene is suspected to have undergone duplication in a certain type of cancer. Which technique can verify gene duplication?
A. Northern blotting
B. Southern blotting
C. South western blotting
D. Western blotting
Q: During anerobic growth, an organism converts Glucose (P) into biomass (Q), Ethanol ®, Acetaldehyde (S) and Glycerol (T). Every mole of carbon in Glucose gets distributed as follows:
A protein expressed in Ecoli under lac promoter and operator. Leaky expression seen in absence of IPTG.
Which of these methods will minimize leaky expression?